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Huagongshe화공사 화학 정보 인쇄 보고서 · 연구 참고용
HRID 2242532생성일: 2026년 10월 27일

Sodium Chloride → Trandolapril

https://huagongshe.com/reaction/2242532

반응식

참여 물질

역할이름HCID투입량
반응물Sodium ChlorideHCID 5234—
반응물Methanaminium, N-((1H-benzotriazol-1-yloxy)(dimethylamino)methylene)-N-methyl-, hexafluorophosphate(1-) (1:1)HCID 2733084—
반응물(2S,3aR,7aS)-octahydro-1H-indole-2-carboxylic acidHCID 7018901—
반응물N-(1-ethoxycarbonyl-3-phenylpropyl)-L-alanineHCID 13044262—
용매DimethylformamideHCID 6228—
용매AcetonitrileHCID 6342—
용매TriethylamineHCID 8471—
생성물TrandolaprilHCID 548472792%

반응 단계

To 2.79 g of (S)-1-(N-(1-(ethoxycarbonyl)-3-phenylpropyl)-L-alanine and 1.75 g of (2S,3aR,7aS)-octahydro-1H-indol-2-carboxylic acid in 100 ml of acetonitrile and 5 ml DMF first 2.9 ml of triethylamine and then with stirring 3.8 g O-(benzotriazol-1-yl)-N,N,N′,N′-tetramethyluronium hexafluorophosphate were and the stirring of the mixture was continued for 30 minutes at room temperature. Finally, 300 ml of saturated NaCl solution was added and the mixture was extracted twice with 100 ml of ethyl acetate. After isolation of the product, which was done by the same way as in example 1, 3.96 g (92%) of trandolapril was obtained.

출처 및 근거

DOI10.6084/m9.figshare.5104873.v1
특허 번호US07671215B2
출처 데이터셋uspto-grants-2010_03
ORD IDord-ea87d675a8b64bf4ac30b3d92c8d90c9
출처 메모uspto-grants-2010_03