2-Aminothiazole → 2-(Allyloxy)-4-methyl-1-nitrobenzene

HRID 2276244

반응식

HRID 2276244 반응식
[CH2:1]([OH:4])[CH:2]=[CH2:3].F[C:6]1[CH:7]=[C:8]([CH3:15])[CH:9]=[CH:10][C:11]=1[N+:12]([O-:14])=[O:13].[CH3:16][C:17]1[CH:23]=[CH:22][C:20]([NH2:21])=[C:19]([O:24][CH2:25][CH:26]=[CH2:27])[CH:18]=1.CC1C=CC(N)=[C:31]([O:36]CC(C)C)C=1.[NH2:41][C:42]1[S:43][CH:44]=[CH:45][N:46]=1>>[CH2:1]([O:4][C:6]1[CH:7]=[C:8]([CH3:15])[CH:9]=[CH:10][C:11]=1[N+:12]([O-:14])=[O:13])[CH:2]=[CH2:3].[CH2:25]([O:24][C:19]1[CH:18]=[C:17]([CH3:16])[CH:23]=[CH:22][C:20]=1[NH:21][C:31]([NH:41][C:42]1[S:43][CH:44]=[CH:45][N:46]=1)=[O:36])[CH:26]=[CH2:27]

참가 물질

7

반응물 5

HCID 21552-AminothiazoleHCID 7858Allyl AlcoholHCID 67966Benzene, 2-fluoro-4-methyl-1-nitro-HCID 246935594-Methyl-2-(2-methylpropoxy)anilineHCID 392358994-Methyl-2-[(prop-2-en-1-yl)oxy]aniline

생성물 2

HCID 135756662-(Allyloxy)-4-methyl-1-nitrobenzene수율 70%HCID 597329611-(2-Allyloxy-4-methyl-phenyl)-3-thiazol-2-yl-urea수율 68%

실험 절차

3-Allyloxy-4-nitrotoluene (0.67 g, 70%) was prepared from allyl alcohol and 3-fluoro-4-nitrotoluene (0.77 g, 5.0 mmol) following the general procedure G. This was reduced to 4-methyl-2-(allyloxy)aniline (0.40 g, 70%) following general procedure B. 1-(2-Allyloxy-4-methyl-phenyl)-3-thiazol-2-yl-urea (196 mg, 68%) was prepared from 4-methyl-2-(2-methylpropoxy)aniline (163 mg, 1.0 mmol) and 2-aminothiazole (100 mg, 1.0 mmol) following the general procedure D.

출처 및 근거

ORD 기록
ord-155ccbdc017b437ab321017e95ef4026
출처 데이터셋
uspto-grants-2015_09
특허 번호
USRE045670E1

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