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Huagongshe화공사 화학 정보 인쇄 보고서 · 연구 참고용
HRID 2280365생성일: 2026년 10월 25일

Iodine → 1~4~-Iodo-1~1~,2~1~:2~3~,3~1~-terphenyl

https://huagongshe.com/reaction/2280365

반응식

참여 물질

역할이름HCID투입량
반응물IodineHCID 807—
반응물Sulfuric AcidHCID 1118—
반응물M-TerphenylHCID 7076—
반응물Hydroiodic acid dihydrateHCID 85613701—
용매Acetic AcidHCID 176—
용매MethanolHCID 887—
생성물1~4~-Iodo-1~1~,2~1~:2~3~,3~1~-terphenylHCID 12378402—
생성물5'-Iodo-m-terphenylHCID 13067230—

반응 단계

A three-necked flask was charged with 250 g of m-terphenyl (ALDRICH), 50 g of hydroiodic acid dihydrate, 75 g of iodine, 750 ml of acetic acid, and 25 ml of concentrated sulfuric acid, and reaction was allowed to proceed at 70° C. for 3 hours. The product was poured into 5 L of methanol and the mixture was stirred for 1 hour and filtrated. The obtained crystals were purified by column chromatography, and recrystallized from acetonitrile to give 64 g of 3′-phenyl-4-iodobiphenyl (Intermediate 4) and 17 g of 3-phenyl-5-iodobiphenyl in the form of white powder. FD-MS and H-NMR analysis identified the powder as Intermediate 4.

출처 및 근거

DOI10.6084/m9.figshare.5104873.v1
특허 번호US09139522B2
출처 데이터셋uspto-grants-2015_09
ORD IDord-a4026af5f96145e1a1263c9b7eb65129
출처 메모uspto-grants-2015_09