Sodium methanethiolate → 6-Methylsulfanyl-[2,2']bipyridin-3-ol
반응식
F[C:2]1[N:7]=[C:6]([C:8]2[CH:13]=[CH:12][CH:11]=[CH:10][N:9]=2)[C:5]([O:14]C)=[CH:4][CH:3]=1.[CH3:16][S-:17].[Na+]>CN(C)C=O>[CH3:16][S:17][C:2]1[N:7]=[C:6]([C:8]2[CH:13]=[CH:12][CH:11]=[CH:10][N:9]=2)[C:5]([OH:14])=[CH:4][CH:3]=1참가 물질
4
반응 조건
- 온도
- 160 °C
실험 절차
6-Fluoro-3-methoxy-[2,2′]bipyridine (12 mg) and sodium thiomethoxide (41 mg) were suspended in N,N-dimethylformamide (1.5 ml), and the suspension was stirred at 160° C. overnight. The reaction solution was cooled to room temperature, the reaction solution was then filtered, and the solvent was removed from the filtrate by distillation under the reduced pressure. The residue was purified by thin layer chromatography using acetone-chloroform to give 6-methylsulfanyl-[2,2′]bipyridin-3-ol (6 mg, yield 47%).