Phosphorus oxide (P4O10) → HCID 21477978, 화합물
반응식
[F:1][C:2]1[C:7]([F:8])=[CH:6][CH:5]=[CH:4][C:3]=1[CH:9](O)[CH2:10][CH2:11][CH2:12][CH2:13][CH2:14][CH2:15][CH2:16][CH3:17].O=P12OP3(OP(OP(O3)(O1)=O)(=O)O2)=O>[Pd]>[F:1][C:2]1[C:7]([F:8])=[CH:6][CH:5]=[CH:4][C:3]=1[CH2:9][CH2:10][CH2:11][CH2:12][CH2:13][CH2:14][CH2:15][CH2:16][CH3:17]참가 물질
4
실험 절차
Quantities: compound from Example 20 (84.6 g, 0.33 mol), phosphorus pentoxide (142 g, 1mol) and 5% palladium-on-charcoal (7 g). The experimental procedure was as described in Example 22.
출처 및 근거
- ORD 기록
- ord-579d262901b749c2b6e55c0d15390d1d
- 출처 데이터셋
- uspto-grants-1997_11
- 특허 번호
- US05683623
반응 노트
불러오는 중…