Bromine → 1-Bromo-2,3,4,5-tetrafluorobenzene

반응식

BrBr.[Br:3][C:4]1[C:9]([F:10])=[C:8]([F:11])[C:7]([F:12])=[C:6]([F:13])[C:5]=1Br>>[Br:3][C:4]1[C:9]([F:10])=[C:8]([F:11])[C:7]([F:12])=[C:6]([F:13])[CH:5]=1

참가 물질

반응물 2

HCID 24408Bromine

HCID 700071,2-Dibromo-3,4,5,6-tetrafluorobenzene

생성물 1

HCID 661771-Bromo-2,3,4,5-tetrafluorobenzene

실험 절차

A residue of 3.9 g consisting of bromine and dibromotetrafluorobenzene remains in the boiler in a ratio of about 1:1. The calculated yield to bromotetrafluorobenzene with respect to the distillate is 33.4%.

출처 및 근거

ORD 기록: ord-1de0843687194eb0904d5e68a0f2cf70
출처 데이터셋: uspto-grants-2002_12
DOI: 10.6084/m9.figshare.5104873.v1
특허 번호: US06492569B1

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