1-(2-Fluorophenyl)butane-1,3-dione → (2S)-2-{[(Z)-3-(2-fluorophenyl)-1-methyl-3-oxo-1-propenyl]amino}-3-{4-[2-(5-methyl-2-phenyl-1,3-oxazol-4-yl)ethoxy]phenyl}propanoic acid
반응식
[NH2:1][C@@H:2]([CH2:6][C:7]1[CH:12]=[CH:11][C:10]([O:13][CH2:14][CH2:15][C:16]2[N:17]=[C:18]([C:22]3[CH:27]=[CH:26][CH:25]=[CH:24][CH:23]=3)[O:19][C:20]=2[CH3:21])=[CH:9][CH:8]=1)[C:3]([OH:5])=[O:4].[F:28][C:29]1[CH:34]=[CH:33][CH:32]=[CH:31][C:30]=1[C:35](=[O:40])[CH2:36][C:37](=O)[CH3:38]>>[F:28][C:29]1[CH:34]=[CH:33][CH:32]=[CH:31][C:30]=1[C:35](=[O:40])/[CH:36]=[C:37](\[NH:1][C@@H:2]([CH2:6][C:7]1[CH:12]=[CH:11][C:10]([O:13][CH2:14][CH2:15][C:16]2[N:17]=[C:18]([C:22]3[CH:27]=[CH:26][CH:25]=[CH:24][CH:23]=3)[O:19][C:20]=2[CH3:21])=[CH:9][CH:8]=1)[C:3]([OH:5])=[O:4])/[CH3:38]참가 물질
3
반응물 2
생성물 1
실험 절차
The title compound was prepared (as described above for the preparation of Example 2) from 100 mg (0.27 mmol) of Intermediate 45 and 58 mg (0.32 mmol) of Intermediate 20 to yield 55 mg of Example 37: TLC (EtOAc/MeOH (7:3): Rf=0.25; 1H NMR (DMSO-d6, 400 MHz) δ11.42 (d, 1H, J=8.93), 7.95 (m. 2H), 7.70 (dd, 1H, J=1.78, 7.69), 7.51 (m, 4H), 7.23 (m, 4H), 6.88 (d, 2H, J=8.50), 5.36 (s, 1H), 4.22 (m, 2H), 4.16 (brs, 1H), 3.18 (m, 1H), 2.94 (m, 2H), 2.84 (m, 1H), 2.40 (s, 3H), 1.70 (s, 3H); low resolution MS (ES−)m/e 545.1 (M-H); RP-HPLC (Vydac C-18, 25 cm×4.6 mm; 30-100% CH3CN in H2O) with 0.1% HCO2H buffer: 30 minutes; 1 mL/min: tr=19.47 min (to=1.43).