Boron tribromide → 3,6,3',4'-Tetrahydroxyflavone

반응식

[O:1]1[C:5]2[CH:6]=[CH:7][C:8]([C:10]3[O:11][C:12]4[C:17]([C:18](=[O:21])[C:19]=3[OH:20])=[CH:16][C:15]([O:22]C)=[CH:14][CH:13]=4)=[CH:9][C:4]=2[O:3]C1.B(Br)(Br)Br>>[OH:3][C:4]1[CH:9]=[C:8]([C:10]2[O:11][C:12]3[C:17]([C:18](=[O:21])[C:19]=2[OH:20])=[CH:16][C:15]([OH:22])=[CH:14][CH:13]=3)[CH:7]=[CH:6][C:5]=1[OH:1]

참가 물질

반응물 2

HCID 25134Boron tribromide

HCID 18372877HCID 18372877, 화합물

생성물 1

HCID 6675813,6,3',4'-Tetrahydroxyflavone수율 50,536,600%

실험 절차

The reaction was conducted according to the same procedure as Example 57 except that 50 mg (159 pmol) of the compound obtained in Example 5 instead of the compound obtained in Example 12 and 5.0 molar equivalents of boron tribromide (BBr3) were used. Then the resulting product was separated by preparative TLC to give 23 mg of the title compound in a yield of 51%.

후처리

customThen the resulting product was separated by preparative TLC

출처 및 근거

ORD 기록: ord-374bb4a5eb744f08b3a7cbc7eb1b3090
출처 데이터셋: uspto-grants-2002_12
DOI: 10.6084/m9.figshare.5104873.v1
특허 번호: US06500846B1

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