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Boron tribromide → HCID 18372893, 화합물

HRID 2301352
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HRID 2301352 반응식
[O:1]1[C:5]2[CH:6]=[CH:7][C:8]([C:10]3[O:11][C:12]4[C:17]([C:18](=[O:21])[C:19]=3[OH:20])=[CH:16][C:15]([O:22][CH3:23])=[CH:14][CH:13]=4)=[CH:9][C:4]=2[O:3]C1.B(Br)(Br)Br>>[OH:3][C:4]1[CH:9]=[C:8]([C:10]2[O:11][C:12]3[C:17]([C:18](=[O:21])[C:19]=2[OH:20])=[CH:16][C:15]([O:22][CH3:23])=[CH:14][CH:13]=3)[CH:7]=[CH:6][C:5]=1[OH:1]
참가 물질실험 절차후처리출처 및 근거반응 노트

참가 물질

3

반응물 2

HCID 25134Boron tribromideHCID 18372877HCID 18372877, 화합물

생성물 1

HCID 18372893HCID 18372893, 화합물수율 58,648,816%

실험 절차

The reaction was conducted according to the same procedure as Example 57 except that 50 mg (159 pmol) of the compound obtained in Example 5 instead of the compound obtained in Example 12 and 1.5 molar equivalents of boron tribromide (BBr3) were used. Then the resulting product was separated by preparative TLC to give 28 mg of the title compound in a yield of 60%.

후처리

  1. customThen the resulting product was separated by preparative TLC

출처 및 근거

ORD 기록
ord-d8e7ca0db34445468cac6ae932a858d2
출처 데이터셋
uspto-grants-2002_12
DOI
10.6084/m9.figshare.5104873.v1
특허 번호
US06500846B1

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