Isopropyl iodide → 2-Fluoro-4-isopropoxy-1-nitrobenzene
반응식
[F:1][C:2]1[CH:3]=[C:4]([OH:11])[CH:5]=[CH:6][C:7]=1[N+:8]([O-:10])=[O:9].I[CH:13]([CH3:15])[CH3:14].C(=O)([O-])[O-].[K+].[K+]>CC(C)=O>[CH:13]([O:11][C:4]1[CH:5]=[CH:6][C:7]([N+:8]([O-:10])=[O:9])=[C:2]([F:1])[CH:3]=1)([CH3:15])[CH3:14]참가 물질
5
실험 절차
By the method of Example 3, Step A, 23.15 g (0.147 mole) of 3-fluoro-4-nitrophenol and 29.92 g (0.175 mole) of 2-iodopropane were reacted in the presence of 20.73 g (0.150 mole) of anhydrous potassium carbonate in 450 mL of acetone, yielding 28.0 g of 4-isopropoxy-2-fluoronitrobenzene as an oil. The NMR was consistent with the proposed structure.
출처 및 근거
- ORD 기록
- ord-dd66cd547acf42eab2d7601f2c383cc7
- 출처 데이터셋
- uspto-grants-1993_11
- 특허 번호
- US05262390
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