4-Fluorobenzyl bromide → HCID 10363010, 화합물

HRID 29900

반응식

HRID 29900 반응식
[Cl:1][C:2]1[CH:7]=[CH:6][C:5]([C:8]2[N:13]=[C:12]([OH:14])[CH:11]=[C:10]([C:15]3[CH:20]=[CH:19][CH:18]=[CH:17][CH:16]=3)[N:9]=2)=[CH:4][CH:3]=1.[F:21][C:22]1[CH:29]=[CH:28][C:25]([CH2:26]Br)=[CH:24][CH:23]=1>>[Cl:1][C:2]1[CH:3]=[CH:4][C:5]([C:8]2[N:13]=[C:12]([O:14][CH2:26][C:25]3[CH:28]=[CH:29][C:22]([F:21])=[CH:23][CH:24]=3)[CH:11]=[C:10]([C:15]3[CH:20]=[CH:19][CH:18]=[CH:17][CH:16]=3)[N:9]=2)=[CH:6][CH:7]=1

참가 물질

3

반응물 2

HCID 680214-Fluorobenzyl bromideHCID 178515558HCID 178515558, 화합물2회

생성물 1

HCID 10363010HCID 10363010, 화합물

실험 절차

The title compound was prepared from 2-(4-chloro-phenyl)-6-phenyl-pyrimidin-4-ol (which was obtained in Intermediate 1) and 4-fluorobenzyl bromide according to Method A; LC retention time 4.35 min; MS: m/z (ESI) 391 (M+H).

출처 및 근거

ORD 기록
ord-230f657d8e3d4a6a8770b3ebd44fd36b
출처 데이터셋
uspto-grants-2008_09
특허 번호
US07423044B2

연결된 노트

불러오는 중…