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Huagongshe화공사 화학 정보 인쇄 보고서 · 연구 참고용
HRID 3027생성일: 2026년 10월 24일

Isobutyric anhydride → methyl(11R,12S,13E,15S,17R)-9-isobutyryloxy-11,15-bis(tert-butyldimethylsiloxy)-17,20-dimethyl-7-thiaprosta-8,13-dienoate

https://huagongshe.com/ko/reaction/3027

반응식

참여 물질

역할이름HCID투입량
반응물Isobutyric anhydrideHCID 7346—
반응물(1E,3S,5R)-1-iodo-3-(tert-butyldimethylsiloxy)-5-methyl-1-noneneHCID 15689554—
반응물(4R)-tert-butyldimethylsiloxy-2-(5-methoxycarbonylpentylthio)-2-cyclopenten-1-oneHCID 131720587—
반응물HCID 178418306HCID 178418306—
반응물C6H9CuHCID 178418419—
용매Hexamethylphosphorous triamideHCID 15355—
생성물methyl(11R,12S,13E,15S,17R)-9-isobutyryloxy-11,15-bis(tert-butyldimethylsiloxy)-17,20-dimethyl-7-thiaprosta-8,13-dienoateHCID 2288379865%

반응 단계

Using as the materials and reagents (1E,3S,5R)-1-iodo-3-(tert-butyldimethylsiloxy)-5-methyl-1-nonene (476 mg, 1.2 mmol), tert-butyllithium (1.54 mol/l, 1.56 ml, 2.4 mmol), 174 mg of 1-hexynylcopper, hexamethylphosphorous triamide (436 μl), (4R)-tert-butyldimethylsiloxy-2-(5-methoxycarbonylpentylthio)-2-cyclopenten-1-one (373 mg, 1 mmol), and isobutyric anhydride (448 μl), the same procedure was performed as in Example 1 to obtain methyl(11R,12S,13E,15S,17R)-9-isobutyryloxy-11,15-bis(tert-butyldimethylsiloxy)-17,20-dimethyl-7-thiaprosta-8,13-dienoate (466 mg, 65%).

출처 및 근거

DOI10.6084/m9.figshare.5104873.v1
특허 번호US05731452
출처 데이터셋uspto-grants-1998_03
ORD IDord-8f870745fc5f496588a513ddc86e1f2b
출처 메모uspto-grants-1998_03