돌아가기
Huagongshe화공사 화학 정보 인쇄 보고서 · 연구 참고용
HRID 3032생성일: 2026년 10월 24일

Pyridine, hydrofluoride (1:1) → methyl(11R,13E,15S)-9-benzoyloxy-11,15-dihydroxy-7-thiaprosta-8,13-dienoate

https://huagongshe.com/ko/reaction/3032

반응식

참여 물질

역할이름HCID투입량
반응물Pyridine, hydrofluoride (1:1)HCID 64774—
반응물methyl(11R,12S,13E,15S)-9-benzoyloxy-11,15-bis(tert-butyldimethylsiloxy)-7-thiaprosta-8,13-dienoateHCID 22883804—
생성물methyl(11R,13E,15S)-9-benzoyloxy-11,15-dihydroxy-7-thiaprosta-8,13-dienoateHCID 2288380588.3%

반응 단계

Using as the material and reagent a hydrogen fluoride-pyridine solution (0.3 ml) and methyl(11R,12S,13E,15S)-9-benzoyloxy-11,15-bis(tert-butyldimethylsiloxy)-7-thiaprosta-8,13-dienoate (239 mg), the same procedure as in Example 2 was performed to obtain methyl(11R,13E,15S)-9-benzoyloxy-11,15-dihydroxy-7-thiaprosta-8,13-dienoate (144 mg, 86%).

출처 및 근거

DOI10.6084/m9.figshare.5104873.v1
특허 번호US05731452
출처 데이터셋uspto-grants-1998_03
ORD IDord-a8c4e36b9c5748c2bdb42724db547b96
출처 메모uspto-grants-1998_03