Aluminium lithium hydride → 3-(3-Chloro-4-methoxymethoxyphenyl)propanol

HRID 322337노트

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HRID 322337 반응식
[Cl:1][C:2]1[CH:3]=[C:4]([CH2:12][CH2:13][C:14](OCC)=[O:15])[CH:5]=[CH:6][C:7]=1[O:8][CH2:9][O:10][CH3:11].[H-].[Al+3].[Li+].[H-].[H-].[H-]>>[Cl:1][C:2]1[CH:3]=[C:4]([CH2:12][CH2:13][CH2:14][OH:15])[CH:5]=[CH:6][C:7]=1[O:8][CH2:9][O:10][CH3:11]

참가 물질

3

실험 절차

In substantially the same manner as in Reference Example 82, ethyl 3-(3-chloro-4-methoxymethoxyphenyl)propionate was subjected to reduction with lithium aluminum hydride to obtain 3-(3-chloro-4-methoxymethoxyphenyl)propanol as an oil. The yield was 97%.

출처 및 근거

ORD 기록
ord-7eb7a663804f46d8b3cc3fa07f3cfc0e
출처 데이터셋
uspto-grants-2001_04
특허 번호
US06211215B1

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