[C:1]([OH:12])(=[O:11])[C:2]1[CH:10]=[CH:9][C:5]([C:6]([OH:8])=[O:7])=[CH:4][CH:3]=1.C([O-])(=O)C.[Cu:17].C(O)=O>CO>[Cu:17].[C:1]([OH:12])(=[O:11])[C:2]1[CH:10]=[CH:9][C:5]([C:6]([OH:8])=[O:7])=[CH:4][CH:3]=10.70 g of terephthalic acid was dissolved under heating in a mixture solvent of 400 cm3 of methanol and 20 cm3 of acetate. After this solution was cooled to the normal temperature, into this solution, a further solution in which 0.95 g of formic acid copper was dissolved in 50 cm3 of methanol was dripped and then this was kept still for a few days. Thereafter, the precipitation product was suction-filtered and dried for 110° C./4 hours, whereby 0.41 g of terephthalic acid copper was obtained.
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