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Huagongshe화공사 화학 정보 인쇄 보고서 · 연구 참고용
HRID 367123생성일: 2026년 10월 23일

Iodoethane → 2-[(4-chlorophenyl)imino]-2,3-dihydro-3-ethyl-4H-pyrido[3,2-e]-1,3-thiazin-4-one

https://huagongshe.com/ko/reaction/367123

반응식

참여 물질

역할이름HCID투입량
반응물IodoethaneHCID 6340—
반응물Lithium hydrideHCID 62714—
반응물4H-Pyrido[3,2-e]-1,3-thiazin-4-one, 2-[(4-chlorophenyl)amino]-HCID 4292070—
생성물2-[(4-chlorophenyl)imino]-2,3-dihydro-3-ethyl-4H-pyrido[3,2-e]-1,3-thiazin-4-oneHCID 2328756858.4%

반응 단계

The reaction procedure of Example 11 was followed except that 900 mg (3.11 mmol) of 2-(4-chloroanilino)-4H-pyrido[3,2-e]-1,3-thiazin-4-one, 25 mg of lithium hydride and 584 mg of ethyl iodide were used. The resulting residue was then purified through silica gel column chromatography (eluant: chloroform) to obtain 577 mg of 2-[(4-chlorophenyl)imino]-2,3-dihydro-3-ethyl-4H-pyrido[3,2-e]-1,3-thiazin-4-one (58%, recrystallized from a mixture of ether and hexane) as a low polarity substance and 61 mg of 2-[N-(4-chlorophenyl)-N-ethylamino]-4H-pyrido[3,2-e]-1,3-thiazin-4-one (6%, recrystallized from ether) as a high polarity substance.

출처 및 근거

DOI10.6084/m9.figshare.5104873.v1
특허 번호US06133258
출처 데이터셋uspto-grants-2000_10
ORD IDord-6a11ca485d61461a93f3976ec20316ef
출처 메모uspto-grants-2000_10