1-Iodopropane → HCID 23287648, 화합물
반응식
[N+:1]([C:4]1[CH:21]=[CH:20][C:7]([NH:8][C:9]2[S:10][C:11]3[N:19]=[CH:18][CH:17]=[CH:16][C:12]=3[C:13](=[O:15])[N:14]=2)=[CH:6][CH:5]=1)([O-:3])=[O:2].[H-].[Li+].[CH2:24](I)[CH2:25][CH3:26]>>[N+:1]([C:4]1[CH:21]=[CH:20][C:7]([N:8]=[C:9]2[N:14]([CH2:24][CH2:25][CH3:26])[C:13](=[O:15])[C:12]3[CH:16]=[CH:17][CH:18]=[N:19][C:11]=3[S:10]2)=[CH:6][CH:5]=1)([O-:3])=[O:2]참가 물질
4
실험 절차
The reaction procedure of Example 11 was followed except that 901 mg (3.0 mmol) of 2-(4-nitroanilino)-4H-pyrido[3,2-e]-1,3-thiazin-4-one, 30 mg of lithium hydride and 612 mg of propyl iodide were used. The resulting residue was then purified through silica gel column chromatography (eluant: chloroform) to obtain 603 mg of 2,3-dihydro-2-[(4-nitrophenyl)imino]-3-propyl-4H-pyrido[3,2-e]-1,3-thiazin-4-one (59%, recrystallized from a mixture of ether and ethanol).