Benzyl Bromide → HCID 23287710, 화합물
반응식
[N+:1]([C:4]1[CH:21]=[CH:20][C:7]([NH:8][C:9]2[S:10][C:11]3[N:19]=[CH:18][CH:17]=[CH:16][C:12]=3[C:13](=[O:15])[N:14]=2)=[CH:6][CH:5]=1)([O-:3])=[O:2].[H-].[Li+].[CH2:24](Br)[C:25]1[CH:30]=[CH:29][CH:28]=[CH:27][CH:26]=1>>[CH2:24]([N:14]1[C:13](=[O:15])[C:12]2[CH:16]=[CH:17][CH:18]=[N:19][C:11]=2[S:10][C:9]1=[N:8][C:7]1[CH:20]=[CH:21][C:4]([N+:1]([O-:3])=[O:2])=[CH:5][CH:6]=1)[C:25]1[CH:30]=[CH:29][CH:28]=[CH:27][CH:26]=1참가 물질
4
실험 절차
The reaction procedure of Example 11 was followed except that 901 mg (3.0 mmol) of 2-(4-nitroanilino)-4H-pyrido[3,2-e]-1,3-thiazin-4-one, 30 mg of lithium hydride and 616 mg of benzyl bromide were used. The resulting residue was then purified through silica gel column chromatography (eluant: chloroform) to obtain 880 mg of 3-benzyl-2,3-dihydro-2-[(4-nitrophenyl)imino]-4H-pyrido[3,2-e]-1,3-thiazin-4-one (75%, recrystallized from a mixture of ether and hexane).