Isopropyl iodide → HCID 23287720, 화합물

반응식

[NH:1]([C:8]1[S:9][C:10]2[N:18]=[CH:17][CH:16]=[CH:15][C:11]=2[C:12](=[O:14])[N:13]=1)[C:2]1[CH:7]=[CH:6][CH:5]=[CH:4][CH:3]=1.[H-].[Li+].[CH:21](I)([CH3:23])[CH3:22]>>[CH:21]([N:13]1[C:12](=[O:14])[C:11]2[CH:15]=[CH:16][CH:17]=[N:18][C:10]=2[S:9][C:8]1=[N:1][C:2]1[CH:3]=[CH:4][CH:5]=[CH:6][CH:7]=1)([CH3:23])[CH3:22]

참가 물질

반응물 3

HCID 6362Isopropyl iodide

HCID 62714Lithium hydride

HCID 122160784H-Pyrido[3,2-e]-1,3-thiazin-4-one, 2-(phenylamino)-

생성물 1

HCID 23287720HCID 23287720, 화합물

실험 절차

The reaction procedure of Example 11 was followed except that 383 mg of 2-anilino-4H-pyrido[3,2-e]-1,3-thiazin-4-one, 14 mg of lithium hydride and 0.15 ml of isopropyl iodide were used. As a result, 144 mg of 3-isopropyl-2-phenylimino-2,3-dihydro-4H-pyrido[3,2-e]-1,3-thiazin-4-one was obtained.