[OH:1][C:2]1[C:9]([O:10][CH2:11][CH2:12]C)=[CH:8][C:5]([CH:6]=[O:7])=[CH:4][C:3]=1[N+]([O-])=O.C[CH2:18][O:19]C(C)=O>>[OH:1][C:2]1[CH:3]=[CH:4][C:5]([CH:6]=[O:7])=[CH:8][C:9]=1[O:10][CH2:11][CH2:12][O:19][CH3:18]Followed the procedure described in Step 3 of Intermediate 65, where the reaction was refluxed for 2 days. Isolated 900 mg, yield 97% after column chromatography (PE: EtOAc=10:1).
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