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Huagongshe화공사 화학 정보 인쇄 보고서 · 연구 참고용
HRID 407611생성일: 2026년 10월 25일

Potassium Acetate → 2-Bromo-6-(6-tert-butyl-8-fluoro-1-oxophthalazin-2(1H)-yl)-4-fluorobenzaldehyde

https://huagongshe.com/reaction/407611

반응식

참여 물질

역할이름HCID투입량
반응물Potassium AcetateHCID 517044—
반응물4,7-Dimethoxy-1,10-phenanthrolineHCID 10462298—
반응물2,6-Dibromo-4-fluorobenzaldehydeHCID 44474666—
반응물6-(tert-Butyl)-8-fluorophthalazin-1(2H)-oneHCID 59473765—
촉매Copper(1+) iodide; Copper(I) iodide; Cuprous iodide; Cuprous iodide (CuI)HCID 24350—
용매1,4-DioxaneHCID 31275—
생성물2-Bromo-6-(6-tert-butyl-8-fluoro-1-oxophthalazin-2(1H)-yl)-4-fluorobenzaldehydeHCID 8668391130%

반응 단계

To a solution of 102a (767 mg, 2.72 mmol), 6-tert-butyl-8-fluorophthalazin-1(2H)-one 101h (300 mg, 1.36 mmol) in dioxane (50 mL) was added KOAc (267 mg, 2.72 mmol), CuI (259 mg, 1.36 mmol), and 4,7-dimethoxy-1,10-phenanthroline (327 mg, 1.36 mmol). After bubbling nitrogen through the resulting solution for 30 min, the mixture was stirred at 90 degree for 10 h. It was allowed to cool down to room temperature and H2O (100 mL) was added. The aqueous layer was separated and extracted with ethyl acetate (2×200 mL). The combined organic layers was washed with brine (100 mL) and dried over sodium sulfate. The drying agent was removed by filtration and the filtrate was concentrated under reduced pressure. The residue was purified on flash column eluting with PE/EA (15:1) to afford 102b (172 mg, 30%). LCMS: [M+H]+ 421. 1H NMR (500 MHz, CDCl3) δ 10.20 (s, 1H), 8.20 (s, 1H), 7.49-7.51 (m, 3H), 7.25 (m, 1H), 1.36 (s, 9H).

출처 및 근거

DOI10.6084/m9.figshare.5104873.v1
특허 번호US08754077B2
출처 데이터셋uspto-grants-2014_06
ORD IDord-a96a7249d9484a8d9fa873d6a3533910
출처 메모uspto-grants-2014_06