Benzyl Bromide → 3-(Benzyloxy)picolinonitrile

반응식

[OH:1][C:2]1[C:3]([C:8]#[N:9])=[N:4][CH:5]=[CH:6][CH:7]=1.C(=O)([O-])[O-].[K+].[K+].[CH2:16](Br)[C:17]1[CH:22]=[CH:21][CH:20]=[CH:19][CH:18]=1>CC(C)=O>[CH2:16]([O:1][C:2]1[C:3]([C:8]#[N:9])=[N:4][CH:5]=[CH:6][CH:7]=1)[C:17]1[CH:22]=[CH:21][CH:20]=[CH:19][CH:18]=1

참가 물질

실험 절차

A suspension of 3-hydroxypicolinonitrile (3.00 g, 25.0 mmol), which was prepared according to “Synthesis” 316 (1983) and “J. Org. Chem.” 48 1375 (1983), potassium carbonate (5.40 g, 39.1 mmol) and benzyl bromide (5.10 g, 29.8 mmol) in acetone (150 mL) was stirred at room temperature for 20 hrs. The reaction mixture was filtrated and the filtrate was evaporated. The residue was purified by column chromatography on silica gel (ethyl acetate/n-hexane=1/3 to 1/2) followed by recrystallization from ethyl acetate/n-hexane=1/4 to give 3-benzyloxypicolinonitrile as a colorless solid (4.354 g, yield; 83%).