Sodium Iodide → 6-(4-Chlorophenyl)hexyl iodide
반응식
[Cl:1][C:2]1[CH:7]=[CH:6][C:5]([CH2:8][CH2:9][CH2:10][CH2:11][CH2:12][CH2:13]Br)=[CH:4][CH:3]=1.[I-:15].[Na+]>CC(C)=O>[Cl:1][C:2]1[CH:7]=[CH:6][C:5]([CH2:8][CH2:9][CH2:10][CH2:11][CH2:12][CH2:13][I:15])=[CH:4][CH:3]=1참가 물질
4
실험 절차
6-(4-Chlorophenyl)hexyl iodide [VIa; Ar is 4-ClC6H4, R is H] was prepared from 17 g. of 6-(4-chlorophenyl)hexyl bromide (Preparation C13) and 10.2 g. of sodium iodide in 325 ml. of acetone, to give 21 g. of product as an oil.
출처 및 근거
- ORD 기록
- ord-728be4e7078947ce9e184a806c6099a8
- 출처 데이터셋
- uspto-grants-1979_10
- 특허 번호
- US04171378
반응 노트
불러오는 중…