4-Bromophenol → HCID 66915512, 화합물
반응식
[Br:1][C:2]1[CH:7]=[CH:6][C:5]([OH:8])=[CH:4][CH:3]=1.[F:9][C:10]1[C:15](B(O)O)=[C:14]([O:19][CH3:20])[CH:13]=[CH:12][CH:11]=1>C(Cl)Cl>[Br:1][C:2]1[CH:7]=[CH:6][C:5]([O:8][C:15]2[C:14]([O:19][CH3:20])=[CH:13][CH:12]=[CH:11][C:10]=2[F:9])=[CH:4][CH:3]=1참가 물질
4
실험 절차
Into a 100 mL round bottom flask was added 4-bromophenol (2.04 g, 11.8 mmol), 6-fluoro-2-methoxyphenylboronic acid (1.00 g, 5.88 mmol), cupric acetate (1.4 g, 7.70 mmol) and DCM (50 mL). TEA (4.0 mL, 29.0 mmol) was then added followed by 4 A° molecular sieves and the reaction mixture was stirred at rt for 48 h. Reaction mixture was then filtered through celite. The filtrate was concentrated in vacuo to give a residue which was purified by silica gel chromatography, eluting with 5% EtOAc in hexane.
후처리
- customReaction mixture
- filtrationwas then filtered through celite
- concentrationThe filtrate was concentrated in vacuo
- customto give a residue which
- customwas purified by silica gel chromatography
- washeluting with 5% EtOAc in hexane
출처 및 근거
- ORD 기록
- ord-cd7ba9ce95f64e3289938e868bfed921
- 출처 데이터셋
- uspto-grants-2013_07
- 특허 번호
- US08481733B2
반응 노트
불러오는 중…