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HRID 456528생성일: 2026년 10월 25일

Methyl iodide → 4-Bromo-2-(methoxymethyl)thiophene

https://huagongshe.com/reaction/456528

반응식

참여 물질

역할이름HCID투입량
반응물Methyl iodideHCID 6328—
반응물Sodium hydrideHCID 24758—
반응물(4-Bromo-2-thienyl)methanolHCID 2795484—
용매TetrahydrofuranHCID 8028—
생성물4-Bromo-2-(methoxymethyl)thiopheneHCID 15018312—

반응 단계

Add sodium hydride (737 mg, 29.23 mmol, 1.10 equivalents, 95%) to a solution containing methyl iodide (1.65 mL, 26.57 mmol, 1.00 equivalents) and (4-bromo-thiophen-2-yl)-methanol (5.13 g, 26.57 mmol, 1.00 equivalents) in tetrahydrofuran (dry, 25 mL). Stir the resulting mixture at room temperature overnight and evaporate. Partition the residue between water (100 mL) and dichloromethane (100 mL). Extract the aqueous layer with dichloromethane (100 mL), combine the organic layers, dry over magnesium sulfate, filter and evaporate to yield the desired product as a yellow oil.

출처 및 근거

DOI10.6084/m9.figshare.5104873.v1
특허 번호US07186724B2
출처 데이터셋uspto-grants-2007_03
ORD IDord-ac324890fddb41bea7ead4ba5dc52f23
출처 메모uspto-grants-2007_03