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Huagongshe화공사 화학 정보 인쇄 보고서 · 연구 참고용
HRID 49989생성일: 2026년 10월 23일

2-Chloroethanol → 4-(2-chloroethoxy)-1H-indole

https://huagongshe.com/ko/reaction/49989

반응식

참여 물질

역할이름HCID투입량
반응물2-ChloroethanolHCID 34—
반응물TriphenylphosphineHCID 11776—
반응물1H-indol-4-olHCID 75421—
반응물ethyl N-ethoxycarbonyliminocarbamateHCID 220568—
용매Diethyl EtherHCID 3283—
용매TetrahydrofuranHCID 8028—
용매Diethylether hexaneHCID 21584099—
생성물4-(2-chloroethoxy)-1H-indoleHCID 10631721—

반응 단계

A solution of 4-hydroxyindole (3.99 g, 30 mmol), 2-chloroethanol (6.03 ml, 90 mmol) and triphenylphosphine (23.6 g, 90 mmol) in tetrahydrofuran is treated with diethyl azodicarboxylate (14.1 ml, 90 mmol) under nitrogen at room temperature, stirred for 2 hr at room temperature and concentrated in vacuo to give a residue. Cooled diethyl ether is added to the residue and the solid triphenylphosphine oxide is precipitated and removed by filtration. The filtrate is concentrated and purified by flash chromatography (silica gel, EtOAc/hexane: 1.5/8.5) to give an oil. After trituration with Et2O/hexane (1/10), the title compound is obtained as a white solid, 4.8 g (82%) mp 60° C., identified by NMR and mass spectral analyses.

출처 및 근거

DOI10.6084/m9.figshare.5104873.v1
특허 번호US06710069B2
출처 데이터셋uspto-grants-2004_03
ORD IDord-af2ab9939a1c410482122c231543542d
출처 메모uspto-grants-2004_03