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3-(2-Fluoro-6-nitrophenyl)propanoic acid → 5-Fluoro-3,4-dihydroquinolin-2(1H)-one

HRID 50858
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인쇄 미리보기

반응식

HRID 50858 반응식
[F:1][C:2]1[CH:7]=[CH:6][CH:5]=[C:4]([N+:8]([O-])=O)[C:3]=1[CH2:11][CH2:12][C:13]([OH:15])=O>CO.[Pd]>[F:1][C:2]1[CH:7]=[CH:6][CH:5]=[C:4]2[C:3]=1[CH2:11][CH2:12][C:13](=[O:15])[NH:8]2
참가 물질실험 절차후처리출처 및 근거반응 노트

참가 물질

4

반응물 1

HCID 156914433-(2-Fluoro-6-nitrophenyl)propanoic acid

생성물 1

HCID 227369425-Fluoro-3,4-dihydroquinolin-2(1H)-one수율 99.5%

시약·촉매·용매 2

HCID 23938Palladium촉매HCID 887Methanol용매

실험 절차

The suspension of 3-(2-fluoro-6-nitrophenyl)propanoic acid (6.0 g, 28 mmol) and 10% Pd-C (300 mg) in MeOH was hydrogenated under H2 (4 atm) for 3 h. After filtration, the filtrate was concentrated in vacuo to afford 5-Fluoro-3,4-dihydroquinolin-2(1H)-one (4.6 g) as a slightly brown solid. This crude product was used in the next step without further purification.

후처리

  1. filtrationAfter filtration
  2. concentrationthe filtrate was concentrated in vacuo

출처 및 근거

ORD 기록
ord-b40c29e6a78948fdbef5b0ea2d4d3f58
출처 데이터셋
uspto-grants-2004_03
DOI
10.6084/m9.figshare.5104873.v1
특허 번호
US06713490B2

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