Methanol → 4-Bromo-3-chlorosulfonyl-benzoic acid methyl ester
반응식
[Br:1][C:2]1[CH:10]=[CH:9][C:5]([C:6]([OH:8])=[O:7])=[CH:4][C:3]=1[S:11]([Cl:14])(=[O:13])=[O:12].O=S(Cl)Cl.[CH3:19]O>>[Br:1][C:2]1[CH:10]=[CH:9][C:5]([C:6]([O:8][CH3:19])=[O:7])=[CH:4][C:3]=1[S:11]([Cl:14])(=[O:12])=[O:13]참가 물질
4
반응 조건
- 온도
- 80 °C
실험 절차
A mixture of 4-bromo-3-chlorosulfonyl-benzoic acid (6.90 g, 23.04 mmol, 1.00 Eq) in SOCl2 (27.41 g, 230.40 mmol, 10.00 Eq) was stirred at 80° C. for 3 hr. Then the solvent was evaporated. The residue was diluted in TOLUENE (50 mL), and MeOH (959.66 mg, 29.95 mmol, 1.30 Eq) was added, the formed mixture was stirred at 110° C. for 2 hr. Solid was formed, and the solvent was evaporated, the solid was washed with PE, and filtered to afford product methyl 4-bromo-3-chlorosulfonyl-benzoate (7.22 g, 23.03 mmol, 99.94% yield) as white solid.