4-(4-Fluorophenyl)phenethyl alcohol → 4-Fluoro-4'-(2-iodoethyl)biphenyl

반응식

Br[C:2]1[CH:7]=[CH:6][C:5]([CH2:8][CH2:9][I:10])=[CH:4][CH:3]=1.[F:11][C:12]1[CH:17]=[CH:16][C:15](C2C=CC(CCO)=CC=2)=[CH:14][CH:13]=1>>[F:11][C:12]1[CH:17]=[CH:16][C:15]([C:2]2[CH:7]=[CH:6][C:5]([CH2:8][CH2:9][I:10])=[CH:4][CH:3]=2)=[CH:14][CH:13]=1

참가 물질

반응물 2

HCID 27591314-(4-Fluorophenyl)phenethyl alcohol

HCID 197022221-Bromo-4-(2-iodoethyl)benzene

생성물 1

HCID 665779344-Fluoro-4'-(2-iodoethyl)biphenyl수율 100%

실험 절차

The title compound (650 mg, 100%) was prepared following the general procedure of step 1, Preparation 2, outlined for 1-bromo-4-(2-iodoethyl)benzene except that 2-(4′-fluorobiphenyl-4-yl)ethanol (430 mg, 1.99 mmol) was used in place of 2-(4-bromophenyl)ethanol. 1H NMR (400 MHz, CHLOROFORM-d) δ ppm 3.23 (t, J=7.69 Hz, 2H) 3.39 (t, J=7.69 Hz, 2H) 7.13 (t, J=8.72 Hz, 2H) 7.24-7.30 (m, 2H) 7.48-7.58 (m, 4H).

후처리

customthe general procedure of step 1, Preparation 2

출처 및 근거

ORD 기록: ord-dc7e09062afc469f97b5ee4be8dc0a5a
출처 데이터셋: uspto-grants-2014_10
DOI: 10.6084/m9.figshare.5104873.v1
특허 번호: US08853258B2

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