Sodium Iodide → 2-Iodo-1-morpholin-4-yl-ethanone

HRID 557203노트

반응식

HRID 557203 반응식
Cl[CH2:2][C:3](=[O:10])[N:4]1[CH2:9][CH2:8][O:7][CH2:6][CH2:5]1.[I-:11].[Na+]>CC(=O)CC.C(OCC)(=O)C>[I:11][CH2:2][C:3](=[O:10])[N:4]1[CH2:9][CH2:8][O:7][CH2:6][CH2:5]1

참가 물질

5

실험 절차

Dissolve 1-chloro-2-oxo-2-(morpholin-4-yl)ethane (7.0 g, 42.8 mmol) and sodium iodide (8.0 g, 53.4 mmol) in 2-butanone (150 mL) and reflux for 3 hours under nitrogen. Dilute with ethyl acetate (200 mL), filter, concentrate under reduced pressure and chromatograph on flash silica using neat ethyl acetate to obtain 9.4 g (86%) of the title compound as a yellow oil.

후처리

  1. temperaturereflux for 3 hours under nitrogen
  2. filtrationfilter
  3. concentrationconcentrate under reduced pressure and chromatograph on flash silica using neat ethyl acetate

출처 및 근거

ORD 기록
ord-994137f221d641ddab06c2229a5332d0
출처 데이터셋
uspto-grants-2011_11
특허 번호
US08058425B2

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