[Br:1][C:2]1[CH:3]=[C:4]([CH2:14]OS(C)(=O)=O)[C:5]([CH2:8]OS(C)(=O)=O)=[N:6][CH:7]=1.CO.[NH3:22]>CO>[Br:1][C:2]1[CH:3]=[C:4]2[CH2:14][NH:22][CH2:8][C:5]2=[N:6][CH:7]=1To a solution of 58 (1 g, crude) in MeOH (5 mL) was added MeOH—NH3 (5 mL) at 0° C. and stirred at rt for overnight. The reaction mixture was evaporated to obtain the desired compound (600 mg, crude) as a brown liquid. Rf: 0.2 (10% MeOH/CHCl3). The crude compound was used in the next step without further purification; (m/z): 199, 201 [MH]+.
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