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HRID 563376생성일: 2026년 10월 25일

4-Fluoroiodobenzene → 1-(4-fluorophenyl)-6-methyl-1H-indazol-5-ol

https://huagongshe.com/reaction/563376

반응식

참여 물질

역할이름HCID투입량
반응물4-FluoroiodobenzeneHCID 9605—
반응물1,2-Diaminocyclohexane, trans-HCID 43806—
반응물Potassium Phosphate, TribasicHCID 62657—
반응물6-methyl-1H-indazol-5-olHCID 22934018—
촉매Copper(1+) iodide; Copper(I) iodide; Cuprous iodide; Cuprous iodide (CuI)HCID 24350—
용매Ethyl AcetateHCID 8857—
용매1,4-DioxaneHCID 31275—
생성물1-(4-fluorophenyl)-6-methyl-1H-indazol-5-olHCID 5925277238%

반응 단계

6-Methyl-1H-indazol-5-ol (5.0 g, 33.7 mmol) was dissolved in 50 mL dry dioxane in a stainless steel pressure tube. Trans-1,2-cyclohexanediamine (2.0 mL, 17 mmol) was added followed by CuI (647 mg, 3.4 mmol) and then K3PO4 12.7 g, 60 mmol). After the addition of 4-fluoro-1-iodobenzene (3.9 mL, 33.7 mmol), the reactor was sealed and heated at 100 C for 24 h. The reactor was cooled and the contents were taken up in EtOAc, filtered through a SiO2 plug with EtOAc and concentrated in vacuo. The crude product was chromatographed on SiO2 using 1:3 EtOAc/hexanes to give 3.1 g (38% yield) of 1-(4-fluorophenyl)-6-methyl-1H-indazol-5-ol. MS found: (M+H)+=242.

출처 및 근거

DOI10.6084/m9.figshare.5104873.v1
특허 번호US08067447B2
출처 데이터셋uspto-grants-2011_11
ORD IDord-76760e771f8a434eb7c889e7fa789c4b
출처 메모uspto-grants-2011_11