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Guanidine Hydrochloride → HCID 178485136, 화합물

HRID 565035
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HRID 565035 반응식
[C:1]([O:5][C:6]([NH:8][CH2:9][CH2:10][CH2:11][O:12][C:13]1[CH:21]=[C:20]2[C:16]([CH:17]=[C:18]([C:23](OCC)=[O:24])[N:19]2C)=[C:15]([C:28]([F:31])([F:30])[F:29])[CH:14]=1)=[O:7])([CH3:4])([CH3:3])[CH3:2].Cl.[NH2:33][C:34]([NH2:36])=[NH:35].[CH3:37][O-].[Na+]>CO>[C:1]([O:5][C:6]([NH:8][CH2:9][CH2:10][CH2:11][O:12][C:13]1[CH:21]=[C:20]2[C:16]([CH:17]=[C:18]([C:23]([N:35]=[C:34]([NH2:36])[NH:33][CH3:37])=[O:24])[NH:19]2)=[C:15]([C:28]([F:31])([F:30])[F:29])[CH:14]=1)=[O:7])([CH3:4])([CH3:3])[CH3:2]
참가 물질실험 절차출처 및 근거반응 노트

참가 물질

5

반응물 3

HCID 5742Guanidine HydrochlorideHCID 10942334Sodium MethoxideHCID 21194039Ethyl 6-(3-tert-butoxycarbonylaminopropoxy)-1-methyl-4-trifluoromethyl-2-indolecarboxylate

생성물 1

HCID 178485136HCID 178485136, 화합물

시약·촉매·용매 1

HCID 887Methanol용매

실험 절차

The reaction was carried out in a manner similar to Example 1 except for using 1.28 g (2.88 mmol) of ethyl 6-(3-tert-butoxycarbonylaminopropoxy)-1-methyl-4-trifluoromethyl-2-indolecarboxylate, 5.50 g (57.6 mmol) of guanidine hydrochloride and 60 ml of methanol solution of 3.11 g (57.6 mmol) of sodium methoxide. 6-(3-tert-Butoxycarbonylaminopropoxy)-1-methyl-4-trifluoromethyl-2-indoloylguanidine was thus obtained in an amount of 0.41 g. This compound, 0.41 g, was treated in a manner similar to Example 114 to give 0.27 g (21.8%) of 6-(3-aminopropoxy)-1-methyl-4-trifluoromethyl-2-indoloylguanidine dihydrochloride.

출처 및 근거

ORD 기록
ord-4a1f2c32546b498b8fe865125905ea53
출처 데이터셋
uspto-grants-2001_01
DOI
10.6084/m9.figshare.5104873.v1
특허 번호
US06169107A

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