Zirconium → Sulfate Ion

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[S:1]([O-:5])([O-:4])(=[O:3])=[O:2].[Zr+4:6].[S:7]([O-:11])([O-:10])(=[O:9])=[O:8].[Zr]>S(=O)(=O)(O)O>[S:1]([O-:5])([O-:4])(=[O:3])=[O:2].[Zr+4:6].[S:7]([O-:11])([O-:10])(=[O:9])=[O:8].[S:1]([O-:5])([O-:4])(=[O:3])=[O:2]

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실험 절차

It will be evident to those skilled in the art that the preparation of an aqueous zirconium sulfate solution by the dissolution of a zirconium compound such as, for example, zirconia in sulfuric acid will result in an aqueous zirconium sulfate solution with a relatively high sulfate ion content. In the practice of the process of the present invention, it has been found to be preferable to add to the aqueous zirconium sulfate solution sufficient of the ammonia source to provide a molar ammonia concentration of twice the difference between the molar concentration of the sulfate and that of the zirconium (i.e. NH3 (moles)=2[Zr(moles)--SO4 (moles)]).