Benzoic Acid → 2-Phenylbenzimidazole

반응식

[C:1]1(C)[CH:6]=[C:5](C)[CH:4]=[C:3](C)[C:2]=1[C:9]1[NH:10][C:11]2[CH:17]=[CH:16][CH:15]=[CH:14][C:12]=2[N:13]=1.C(O)(=O)C1C=CC=CC=1>>[C:2]1([C:9]2[NH:13][C:12]3[CH:14]=[CH:15][CH:16]=[CH:17][C:11]=3[N:10]=2)[CH:1]=[CH:6][CH:5]=[CH:4][CH:3]=1

참가 물질

반응물 2

HCID 243Benzoic Acid

HCID 227347972-Mesitylbenzimidazole

생성물 1

HCID 128552-Phenylbenzimidazole수율 88%

실험 절차

2-Phenylbenzimidazole was synthesized in a similar way to 2-mesityl-benzimidazole, except using benzoic acid instead of 2,4,6-trimethylbenzoic acid. Molar amounts of carboxylic acid and diamine used were as previously described to provide an off-white powder in 88% yield.

후처리

customto provide an off-white powder in 88% yield

출처 및 근거

ORD 기록: ord-b339cf7b011d45e1bc198a377b43fae5
출처 데이터셋: uspto-grants-2016_04
DOI: 10.6084/m9.figshare.5104873.v1
특허 번호: US09315630B2

반응 노트

불러오는 중…