반응식
[CH3:1][O:2][C:3]1[CH:11]=[C:7]([C:8]([OH:10])=[O:9])[C:6]([NH2:12])=[CH:5][CH:4]=1.Cl.Cl[C:15]1[CH:20]=[CH:19][N:18]=[CH:17][CH:16]=1>>[CH3:1][O:2][C:3]1[CH:4]=[CH:5][C:6]([NH:12][C:15]2[CH:20]=[CH:19][N:18]=[CH:17][CH:16]=2)=[C:7]([CH:11]=1)[C:8]([OH:10])=[O:9]참가 물질
3
실험 절차
5-Methoxy-2-(4-pyridinylamino)benzoic acid was prepared from 4.9 g of 5-methoxyanthranilic acid and 4.4 g of 4-chloropyridine hydrochloride according to the procedure of Example 1, part (a). There was obtained 8.0 g of 5-methoxy-2-(4-pyridinylamino)benzoic acid which was recrystallized from water and used directly in the next reaction.
출처 및 근거
- ORD 기록
- ord-3dc619b6ebe644b1beae46073ca5a95e
- 출처 데이터셋
- uspto-grants-1986_09
- 특허 번호
- US04610991
연결된 노트
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