6-(Bromomethyl)-1-methylquinolin-2(1H)-one → (2S,4R)-4-[5-fluoro-3-(1,2-dihydro-1-methyl-2-oxoquinolin-6-ylmethoxy)phenyl]-4-methoxy-2-methyltetrahydropyran

HRID 654821노트

반응식

HRID 654821 반응식
Br[CH2:2][C:3]1[CH:4]=[C:5]2[C:10](=[CH:11][CH:12]=1)[N:9]([CH3:13])[C:8](=[O:14])[CH:7]=[CH:6]2.[F:15][C:16]1[CH:17]=[C:18]([OH:31])[CH:19]=[C:20]([C@@:22]2([O:29][CH3:30])[CH2:27][CH2:26][O:25][C@@H:24]([CH3:28])[CH2:23]2)[CH:21]=1>>[F:15][C:16]1[CH:17]=[C:18]([O:31][CH2:2][C:3]2[CH:4]=[C:5]3[C:10](=[CH:11][CH:12]=2)[N:9]([CH3:13])[C:8](=[O:14])[CH:7]=[CH:6]3)[CH:19]=[C:20]([C@@:22]2([O:29][CH3:30])[CH2:27][CH2:26][O:25][C@@H:24]([CH3:28])[CH2:23]2)[CH:21]=1

참가 물질

3

반응물 2

HCID 151990656-(Bromomethyl)-1-methylquinolin-2(1H)-oneHCID 22845134(2S,4R)-4-(5-fluoro-3-hydroxyphenyl)-4-methoxy-2-methyltetrahydropyran

생성물 1

HCID 10364303(2S,4R)-4-[5-fluoro-3-(1,2-dihydro-1-methyl-2-oxoquinolin-6-ylmethoxy)phenyl]-4-methoxy-2-methyltetrahydropyran수율 66%

실험 절차

Using the procedure described in Example 1, 6-bromomethyl-1,2-dihydro-1-methylquinolin-2-one was reacted with (2S,4R)-4-(5-fluoro-3-hydroxyphenyl)-4-methoxy-2-methyltetrahydropyran to give (2S,4R)-4-[5-fluoro-3-(1,2-dihydro-1-methyl-2-oxoquinolin-6-ylmethoxy)phenyl]-4-methoxy-2-methyltetrahydropyran in 66% yield, m.p. 91°-93° C.

출처 및 근거

ORD 기록
ord-495963923d464b5dbd4ec6f3d6479f27
출처 데이터셋
uspto-grants-1992_07
특허 번호
US05134148

반응 노트

불러오는 중…