Methanol → (7-Fluoro-quinolin-6-yl)-acetic acid methyl ester

HRID 655251노트

반응식

HRID 655251 반응식
[F:1][C:2]1[CH:11]=[C:10]2[C:5]([CH:6]=[CH:7][CH:8]=[N:9]2)=[CH:4][C:3]=1[CH2:12][C:13]([OH:15])=[O:14].OS(O)(=O)=O.[CH3:21]O>C(OCC)(=O)C>[CH3:21][O:14][C:13](=[O:15])[CH2:12][C:3]1[CH:4]=[C:5]2[C:10](=[CH:11][C:2]=1[F:1])[N:9]=[CH:8][CH:7]=[CH:6]2

참가 물질

5

실험 절차

To a solution of (7-fluoro-quinolin-6-yl)-acetic acid (13.4 g, 65.36 mmol) in methanol (140 mL) was added conc.H2SO4 (3.5 mL, 68.63 mmol). The reaction mixture was concentrated to give a brown residue, which was diluted with 100 ml of ethyl acetate, washed with sat. aq. NaHCO3 and brine, then the organic layer was dried over anhydrous Na2SO4, and concentrated to give (7-fluoro-quinolin-6-yl)-acetic acid methyl ester as yellow solid (14.0 g, yield: 98%).

후처리

  1. concentrationThe reaction mixture was concentrated
  2. customto give a brown residue, which
  3. washwashed with sat. aq. NaHCO3 and brine
  4. dry with materialthe organic layer was dried over anhydrous Na2SO4
  5. concentrationconcentrated

출처 및 근거

ORD 기록
ord-a246ffe110d644489761b10db1a7e158
출처 데이터셋
uspto-grants-2011_12
특허 번호
US08071581B2

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