[CH3:1][N:2]([C:4]([NH:6][C:7]([NH2:9])=[NH:8])=[NH:5])[CH3:3].[C:10]([OH:18])(=[O:17])[CH2:11][CH2:12][CH2:13][C:14]([OH:16])=[O:15]>C(O)C>[CH3:1][N:2]([C:4]([NH:6][C:7]([NH2:9])=[NH:8])=[NH:5])[CH3:3].[C:10]([O-:18])(=[O:17])[CH2:11][CH2:12][CH2:13][C:14]([O-:16])=[O:15]9.75 g (2.5 molar equivalents) of metformin free-base was stirred in 100 ml of ethanol at room temperature, after which a solution of 3.98 g (1 molar equivalent) of glutaric acid in ethanol was added dropwise thereto and stirred at 10° C. The produced crystal was filtered and dried in hot air, thus obtaining 7.41 g (yield: 62.8%) of metformin glutarate.
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