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Huagongshe화공사 화학 정보 인쇄 보고서 · 연구 참고용
HRID 6909생성일: 2026년 10월 24일

Water → 3-Fluoro-4-methoxyphenol

https://huagongshe.com/ko/reaction/6909

반응식

참여 물질

역할이름HCID투입량
반응물WaterHCID 962—
반응물m-Chloroperbenzoic acidHCID 70297—
반응물1-(3-Fluoro-4-methoxyphenyl)ethan-1-oneHCID 96828—
반응물Lithium hydroxide, monohydrateHCID 168937—
용매MethanolHCID 887—
용매DichloromethaneHCID 6344—
생성물3-Fluoro-4-methoxyphenolHCID 1466161372.7%

반응 단계

A solution of 3′-fluoro-4′-methoxyacetophenone (10 g; 59 mmol) and m-chloroperbenzoic acid (50% purity; 30 g; 89 mmol) in CH2Cl2 (300 mL) was stirred at RT overnight. The solution was washed with saturated aqueous Na2CO3, then filtered through a pad of SiO2 (CH2Cl2 as eluent) and finally chromatographed (SiO2; hex:EtOAc 4:1) to give the crude product (3′-fluoro-4′-methoxy phenyl acetate; 63 g). A solution of this crude material and LiOH.H2O (5 g; 120 mmol) in MeOH:H2O (100 mL of a 9:1 mixture) was stirred at RT overnight. Volatiles were removed in vacuo, and the residue was partitioned between excess aqueous 1 M HCl and EtOAc (aqueous layer pH˜3). The aqueous phase was extracted with EtOAc (2×). The combined organic extracts were dried (Na2SO4) and concentrated in vacuo to give 3-fluoro-4-methoxy phenol (6.1 g; 72%) as an oil.

출처 및 근거

DOI10.6084/m9.figshare.5104873.v1
특허 번호US07084162B2
출처 데이터셋uspto-grants-2006_08
ORD IDord-a38c84e2ef9f48209dd841a26f28b318
출처 메모uspto-grants-2006_08