5,6-Dimethoxy-1,2,3,4-tetrahydroisoquinoline hydrochloride → 2-[[2-(4-Fluorophenyl)quinazolin-4-yl]carbonyl]-5,6-dimethoxy-1,2,3,4-tetrahydroisoquinoline

HRID 717391노트

반응식

HRID 717391 반응식
[F:1][C:2]1[CH:7]=[CH:6][C:5]([C:8]2[N:17]=[C:16]([C:18](O)=[O:19])[C:15]3[C:10](=[CH:11][CH:12]=[CH:13][CH:14]=3)[N:9]=2)=[CH:4][CH:3]=1.Cl.[CH3:22][O:23][C:24]1[C:33]([O:34][CH3:35])=[CH:32][CH:31]=[C:30]2[C:25]=1[CH2:26][CH2:27][NH:28][CH2:29]2>>[F:1][C:2]1[CH:3]=[CH:4][C:5]([C:8]2[N:17]=[C:16]([C:18]([N:28]3[CH2:27][CH2:26][C:25]4[C:30](=[CH:31][CH:32]=[C:33]([O:34][CH3:35])[C:24]=4[O:23][CH3:22])[CH2:29]3)=[O:19])[C:15]3[C:10](=[CH:11][CH:12]=[CH:13][CH:14]=3)[N:9]=2)=[CH:6][CH:7]=1

참가 물질

3

반응물 2

HCID 717574045,6-Dimethoxy-1,2,3,4-tetrahydroisoquinoline hydrochlorideHCID 904114972-(4-Fluorophenyl)quinazoline-4-carboxylic acid

생성물 1

HCID 862688132-[[2-(4-Fluorophenyl)quinazolin-4-yl]carbonyl]-5,6-dimethoxy-1,2,3,4-tetrahydroisoquinoline수율 10%

실험 절차

Reaction of 2-(4-fluorophenyl)quinazoline-4-carboxylic acid with 5,6-dimethoxy-1,2,3,4-tetrahydroisoquinoline hydrochloride gave compound 3 (10% yield) as a white solid. 1H NMR (300 MHz, DMSO-d6) δ 2.72 and 2.98 (2t, 2H), 3.49 and 4.03 (2t, 2H), 3.68 and 3.75 (2s, 3H), 3.76 and 3.81 (2s, 3H), 4.42 and 4.93 (2s, 2H), 6.63 and 7.01 (2d, 1H), 6.81 and 7.08 (2d, 1H), 7.37-7.44 (m, 2H), 7.76-7.79 (m, 1H), 7.89-7.99 (2d, 1H), 8.07-8.15 (m, 2H), 8.53-8.62 (m, 2H); MS (ESI) m/z 444 ([M+H]+).

출처 및 근거

ORD 기록
ord-c615b0ea72c04f59a90759dc7c6af08c
출처 데이터셋
uspto-grants-2015_11
특허 번호
US09193707B2

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