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HRID 72103생성일: 2026년 10월 23일

1-Bromo-2-fluorobenzene → 5-(2-Fluorophenyl)pent-4-yn-1-ol

https://huagongshe.com/ko/reaction/72103

반응식

참여 물질

역할이름HCID투입량
반응물1-Bromo-2-fluorobenzeneHCID 61259—
반응물4-Pentyn-1-olHCID 79346—
촉매Copper(1+) iodide; Copper(I) iodide; Cuprous iodide; Cuprous iodide (CuI)HCID 24350—
촉매HCID 178418397HCID 178418397—
용매AcetonitrileHCID 6342—
생성물5-(2-Fluorophenyl)pent-4-yn-1-olHCID 86687856—

반응 단계

1-Bromo-2-fluorobenzene [1072-85-1] (3.0 g, 17 mmol, 1.0 equiv) and pent-4-yn-1-ol [5390-04-5] (2.3 mL, 25 mmol, 1.5 equiv) were dissolved in acetonitrile (40 mL). CuI (0.13 g, 0.68 mmol, 0.04 equiv) and TEA (3.4 mL, 25 mmol, 1.5 equiv) was added to the stirred solution followed by tetrakis(triphenylphosphine)palladium(0) (0.39 g, 0.34 mmol, 0.02 equiv). The solution was heated at reflux for 16 hours. The solution was cooled, filtered through Celite, the Celite pad rinsed with EtOAc and the solvent removed by rotoevaporation. Column chromatography (9:1 hexanes:ethyl acetate) of the residue afforded pure 5-(2-fluorophenyl)pent-4-yn-1-ol Intermediate 60 (1.3 g, 43%).

출처 및 근거

DOI10.6084/m9.figshare.5104873.v1
특허 번호US08828973B2
출처 데이터셋uspto-grants-2014_09
ORD IDord-aba1e866d2cd413daa1a31e8afd20c22
출처 메모uspto-grants-2014_09