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Huagongshe화공사 화학 정보 인쇄 보고서 · 연구 참고용
HRID 7476생성일: 2026년 10월 27일

Hydrochloric Acid → 4-Chloro-6-methoxy-7-(4-pyridylmethoxy)cinnoline hydrochloride

https://huagongshe.com/reaction/7476

반응식

참여 물질

역할이름HCID투입량
반응물Hydrochloric AcidHCID 313—
반응물IsopropanolHCID 3776—
반응물4-HydroxymethylpyridineHCID 11472—
반응물TributylphosphineHCID 13831—
반응물1,1'-(Azodicarbonyl)dipiperidineHCID 73042—
반응물4-Chloro-7-hydroxy-6-methoxycinnolineHCID 135752523—
용매DichloromethaneHCID 6344—
생성물4-Chloro-6-methoxy-7-(4-pyridylmethoxy)cinnoline hydrochlorideHCID 21991011122%

반응 단계

The starting material, 4-chloro-6-methoxy-7-(4-pyridylmethoxy)cinnoline hydrochloride, was obtained by adding 4-chloro-7-hydroxy-6-methoxycinnoline (200 mg, 0.95 mmol), followed by 4-hydroxymethylpyridine (108 mg, 1 mmol) and 1,1′-(azodicarbonyl)dipiperidine (647 mg, 2.5 mmol), in portions, to a solution of tri(n-butyl)phosphine (640 μg, 2.5 mmol) in methylene chloride (6 ml). After stirring for 1 hour at ambient temperature, a solution of 7M hydrogen chloride in isopropanol (300 μl, 2.1 mmol) was added. The resulting solid was filtered off, washed with methylene chloride and ether to give 4-chloro-6-methoxy-7-(4-pyridylmethoxy)cinnoline hydrochloride as a solid (196 mg, 55%).

출처 및 근거

DOI10.6084/m9.figshare.5104873.v1
특허 번호US07087602B2
출처 데이터셋uspto-grants-2006_08
ORD IDord-1925b59d42954b6c9cf79949b3a51998
출처 메모uspto-grants-2006_08