4-Hydroxybenzaldehyde → 4-((2-Fluorophenyl)methoxy)benzaldehyde

반응식

[OH:1][C:2]1[CH:9]=[CH:8][C:5]([CH:6]=[O:7])=[CH:4][CH:3]=1.[F:10][C:11]1[CH:18]=[CH:17][CH:16]=[CH:15][C:12]=1[CH2:13]Cl>>[F:10][C:11]1[CH:18]=[CH:17][CH:16]=[CH:15][C:12]=1[CH2:13][O:1][C:2]1[CH:9]=[CH:8][C:5]([CH:6]=[O:7])=[CH:4][CH:3]=1

참가 물질

반응물 2

HCID 1264-Hydroxybenzaldehyde

HCID 9580Benzene, 1-(chloromethyl)-2-fluoro-

생성물 1

HCID 7027174-((2-Fluorophenyl)methoxy)benzaldehyde

실험 절차

4-(2-Fluorobenzyloxy)benzaldehyde is prepared by alkylation of 4-hydroxybenzaldehyde (0.39 g) with 2-fluorobenzyl chloride by following the same procedure of Example 1, but using three different phase transfer catalysts.

출처 및 근거

ORD 기록: ord-d79eb389a07c4d7285ec178273645986
출처 데이터셋: uspto-grants-2014_09
DOI: 10.6084/m9.figshare.5104873.v1
특허 번호: US08846763B2

반응 노트

불러오는 중…