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Huagongshe화공사 화학 정보 인쇄 보고서 · 연구 참고용
HRID 839157생성일: 2026년 10월 26일

2,4-Hexanedione → 3-[3-Ethyl-6-(3,4-methylenedioxyphenyl)-3-hexenyl]-2,4-hexanedione

https://huagongshe.com/reaction/839157

반응식

참여 물질

역할이름HCID투입량
반응물2,4-HexanedioneHCID 76355—
반응물LithiumHCID 3028194—
반응물3-Ethyl-6-(3,4-methylenedioxyphenyl)-3-hexenyl iodideHCID 54373451—
용매DimethylformamideHCID 6228—
생성물3-[3-Ethyl-6-(3,4-methylenedioxyphenyl)-3-hexenyl]-2,4-hexanedioneHCID 514303—

반응 단계

[I; Ar is 3,4-methylenedioxyphenyl, R0 is H, R' is CH3CO, R" is CH3CH2CO, Y is C(C2H5)=CHCH2CH2 ] was prepared from 23.2 g. of 3-ethyl-6-(3,4-methylenedioxyphenyl)-3-hexenyl iodide (Preparation D1) and 22.3 g. of the lithium salt of 2,4-hexanedione (prepared by the procedure described in Example 8 below) in 300 ml. of dimethylformamide according to the procedure described above in Example 2. There was thus obtained 21 g. of crude product which was chromatographed on 600 g. of silica gel in pentane solution containing 20% benzene. The column was eluted with the pentane-benzene-ether solvent series. Benzene containing 3% ether brought out the desired product, 14.5 g. of 3-[3-ethyl-6-(3,4-methylenedioxyphenyl)-3-hexenyl]-2,4-hexanedione as a yellow oil.

출처 및 근거

DOI10.6084/m9.figshare.5104873.v1
특허 번호US04093736
출처 데이터셋uspto-grants-1978_06
ORD IDord-2891f5efe7234ffea56fbb1638de4f3c
출처 메모uspto-grants-1978_06