Pentadecanoic Acid → Pentadecanoyl chloride
반응식
[C:1]([OH:17])(=O)[CH2:2][CH2:3][CH2:4][CH2:5][CH2:6][CH2:7][CH2:8][CH2:9][CH2:10][CH2:11][CH2:12][CH2:13][CH2:14][CH3:15].S(Cl)([Cl:20])=O>C1CCCCC1>[C:1]([Cl:20])(=[O:17])[CH2:2][CH2:3][CH2:4][CH2:5][CH2:6][CH2:7][CH2:8][CH2:9][CH2:10][CH2:11][CH2:12][CH2:13][CH2:14][CH3:15]참가 물질
4
반응 조건
- 온도
- 80 °C
실험 절차
In a one L (liter) two-necked flask were placed 160.0 g (0.66 mol) of pentadecanoic acid and 200 milliliter (mL) of cyclohexane, and the flask was equipped with a 100 mL dropping funnel containing 83.3 g (0.7 mol) of thionyl chloride and a reflux tube. Then, the pentadecanoic acid was completely dissolved under heating and stirring of the flask in an oil bath at 80° C. Thereafter the thionyl chloride was added dropwise over a period of 2 hours, and further the oil bath was maintained at 80° C. for one hour. From the resultant reaction mixture were removed the cyclohexane and the thionyl chloride under reduced pressure by means of an aspirator. The resultant crude reaction product was subjected to vacuum distillation. Thus 110.0 g (0.42 mol) of pentadecanoyl chloride was obtained in a yield of 63.9% based on the fed pentadecanoic acid.