Aniline → 1-Naphthol

반응식

N[C:2]1[CH:11]=[C:10](S(O)(=O)=O)[CH:9]=[C:8]2[C:3]=1[C:4]([OH:20])=[CH:5][C:6](S(O)(=O)=O)=[CH:7]2.ClC1N=C(Cl)N=C(Cl)N=1.NC1C=CC=CC=1>>[CH:10]1[CH:11]=[CH:2][C:3]2[C:8](=[CH:7][CH:6]=[CH:5][C:4]=2[OH:20])[CH:9]=1

참가 물질

반응물 3

HCID 6115Aniline

HCID 7009H acid

HCID 7954Cyanuric chloride

생성물 1

HCID 70051-Naphthol

실험 절차

In an aqueous solvent, 31.9 parts of 5-amino-4-hydroxynaphthalene-2,7-disulfonic acid was condensed with 18.4 parts of 2,4,6-trichloro-s-triazine according to a normal method and the resultant condensate was condensed with 28.1 parts of 3-(2-sulfate ethylsulfonyl)aniline according to a normal method. The product thus obtained was condensed with 9.3 parts of aniline according to a normal method to obtain a naphthol derivative.