[Cl:1][C:2]1[CH:7]=[CH:6][C:5]([CH2:8][C:9]([OH:11])=[O:10])=[CH:4][CH:3]=1.Cl[C:13]1C=CC=CC=1C(C)C(O)=O>>[Cl:1][C:2]1[CH:3]=[CH:4][C:5]([CH:8]([CH3:13])[C:9]([OH:11])=[O:10])=[CH:6][CH:7]=1The titled compound was prepared from p-chlorophenylacetic acid in 73% yield in the same manner as the preparation of 2-(2-Chlorophenyl)propionic acid in Example 184a. MS (ESI) 185 (MH+).
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