Sodium Bicarbonate → N-methyl-N-(2-ethoxycarbonylbenzyl)-3-ethoxycarbonylmethylaniline

반응식

[CH3:1][NH:2][C:3]1[CH:8]=[CH:7][CH:6]=[C:5]([CH2:9][C:10]([O:12][CH2:13][CH3:14])=[O:11])[CH:4]=1.C(=O)([O-])O.[Na+].Br[CH2:21][C:22]1[CH:32]=[CH:31][CH:30]=[CH:29][C:23]=1[C:24]([O:26][CH2:27][CH3:28])=[O:25]>O>[CH3:1][N:2]([CH2:21][C:22]1[CH:32]=[CH:31][CH:30]=[CH:29][C:23]=1[C:24]([O:26][CH2:27][CH3:28])=[O:25])[C:3]1[CH:8]=[CH:7][CH:6]=[C:5]([CH2:9][C:10]([O:12][CH2:13][CH3:14])=[O:11])[CH:4]=1

참가 물질

실험 절차

The starting material employed above had been synthesized in the same manner as described in Example 1. That is, N-methyl-3-ethoxycarbonylmethylaniline (20.7 g), sodium hydrogencarbonate (19 g), water (30 ml) and ethyl 2-bromomethylbenzoate (27.5 g) were used to produce N-methyl-N-(2-ethoxycarbonylbenzyl)-3-ethoxycarbonylmethylaniline (26 g) as a light yellow oil. Then, N-methyl-N-(2-ethoxycarbonylbenzyl)-3-ethoxycarbonylmethylaniline (26 g) so produced, sodium hydroxide (40 g), water (450 ml) and ethanol (150 ml) were used to prepare N-methyl-N-(2-carboxybenzyl)-3-carboxymethylaniline (14.8 g).