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Thiazolidine → [5-(3-Chloro-5-fluoro-phenyl)-1-(2-methyl-4-pyridyl)pyrazol-3-yl]-thiazolidin-3-yl-methanone

HRID 930058
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HRID 930058 반응식
[Cl:1][C:2]1[CH:3]=[C:4]([C:9]2[N:13]([C:14]3[CH:19]=[CH:18][N:17]=[C:16]([CH3:20])[CH:15]=3)[N:12]=[C:11]([C:21](O)=[O:22])[CH:10]=2)[CH:5]=[C:6]([F:8])[CH:7]=1.ClC1C=C(C2N(C3C=NC=CC=3)N=C(C(N3CCNC(=O)C3)=O)C=2)C=C(F)C=1.[S:52]1[CH2:56][CH2:55][NH:54][CH2:53]1>>[Cl:1][C:2]1[CH:3]=[C:4]([C:9]2[N:13]([C:14]3[CH:19]=[CH:18][N:17]=[C:16]([CH3:20])[CH:15]=3)[N:12]=[C:11]([C:21]([N:54]3[CH2:55][CH2:56][S:52][CH2:53]3)=[O:22])[CH:10]=2)[CH:5]=[C:6]([F:8])[CH:7]=1
참가 물질실험 절차출처 및 근거반응 노트

참가 물질

4

반응물 3

HCID 10444ThiazolidineHCID 715765334-[5-(3-Chloro-5-fluoro-phenyl)-1-(3-pyridyl)pyrazole-3-carbonyl]piperazin-2-oneHCID 896026175-(3-Chloro-5-fluorophenyl)-1-(2-methylpyridin-4-yl)-1H-pyrazole-3-carboxylic acid

생성물 1

HCID 86574284[5-(3-Chloro-5-fluoro-phenyl)-1-(2-methyl-4-pyridyl)pyrazol-3-yl]-thiazolidin-3-yl-methanone

실험 절차

150 mg (0.45 mmol) of the compound of Example 30A is reacted analogously to the synthesis of the compound of Example 4 with 43 mg (0.48 mmol) of thiazolidine. 137 mg (74% of theory) of the title compound is obtained.

출처 및 근거

ORD 기록
ord-de177400e41948f2a75ff93ce1a9d0ac
출처 데이터셋
uspto-grants-2016_03
DOI
10.6084/m9.figshare.5104873.v1
특허 번호
US09296720B2

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